Monster Hunt

About Monster Hunt

BGaming has released Johnny vs Chicken, a slot that pulls two recurring characters out of separate franchises and stages a head-to-head between them. The Johnny Cash character, from titles including Johnny Cash Train Heist and Johnny Cash Gold Rush, draws pistols with the lead sheriff from Chicken Rush.

The news here isn’t really about a single Wild West slot. It’s about how BGaming is treating its existing intellectual property. Rather than launching another standalone theme, the studio is connecting characters that already carry their own player recognition, a crossover approach more common to entertainment franchises than to slot catalogs.

The game arrived on September 15, 2026, and forms part of BGaming’s Entertainment line.

How to play Monster Hunt

Instead, it proposed a risk-based approach. It suggested lighter controls on use cases such as coding assistants, but strong checks on customer-facing functions, particularly those involving fraud and responsible gambling.

Kenneth Brincat, CEO of the MDIA, said companies needed “practical ways” to better understand where AI fits within their businesses.

“Trust is fundamental to the responsible adoption of AI. As its use becomes increasingly embedded across the gaming sector, organisations need practical ways to understand where AI is being used, manage the associated risks and ensure that accountability and human oversight remain firmly in place,” he said.

How to play Monster Hunt

Wilson expects others to follow.

For Wilson, the bigger point is not who else may follow, but why operators need these tools in the first place. Splash Tech was built to help operators make existing content portfolios work harder, using free-to-play experiences and a supplier-agnostic jackpot engine to drive engagement, retention, cross-sell and lifetime value across casino, sportsbook and third-party content.

Jackpots and free-to-play may be very different propositions, but Wilson judges both against the same unromantic measure: whether they produce value for the operator.